math:calculus

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math:calculus [2019/12/22 22:44] – [Derivative] phreazermath:calculus [2019/12/22 23:10] – [Differential equations] phreazer
Line 16: Line 16:
  
 $f'(x) = \frac{d}{dx} f(x) = \lim_{h -> 0} \frac{f(x + h) - f(x)}{h}$ $f'(x) = \frac{d}{dx} f(x) = \lim_{h -> 0} \frac{f(x + h) - f(x)}{h}$
 +
 +$f''(x) = \frac{d^2}{dx^2} f(x)$
  
 Geometrically, derivative of f at point x=a is slope of tangent line.  Geometrically, derivative of f at point x=a is slope of tangent line. 
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 Differential operator Differential operator
  
-$y' = 2y + x^2$ => $f'(x)=2*f(x)+x^2$ =$\frac{dy}{dx} = 2y + x^2$+$f'(x)=f(x)^2 * x
 + 
 +$\frac{dy}{dx} = y^2 * x$ 
 + 
 +$dy y^2 * x {dx}$ 
 + 
 +$\frac{1}{y^2} dy = x {dx}
 + 
 +$\int \frac{1}{y^2} dy = \int x {dx}
 + 
 +$-y^{-1} + c_1 1/2 x^2 c_2$ 
 + 
 +$-(1/y)  = 1/2 x^2 + c_2 - c_1$ $(c_2 - c_1 = c)$
  
 +$y = \frac{-1}{(1/2 x^2 + c)}$ (y is a function not value, obviously)
  • math/calculus.txt
  • Last modified: 2019/12/22 23:28
  • by phreazer